Math, asked by sharmanikita00001, 3 months ago

if 3x+2y=12 and xy=6, find the value of <br /> {9x}^{2}  +  {4y}^{2} <br />.( hint: use identity<br /> {(x + y)}^{2}  =  {x}^{2}  +  {y}^{2}  + 2xy<br /> to substitute values)​

Answers

Answered by Shivam1148
0

Step-by-step explanation:

3x+2y=12

sq. bith sides

9x²+4y²+12xy=144

=144-12(6)

=12(12-6)

=12×6

=72

Similar questions