Math, asked by singhbabita3114, 2 months ago

If 3x+2y = 12and xy= 6,find the value 9x2+4y2​

Answers

Answered by pprasanna06
0

Answer:

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Step-by-step explanation:

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Attachments:
Answered by riddhibharwaj
0

Answer:

9x^2  +4y^ 2 =72

Step-by-step explanation:

3x+2y=12

Squaring both sides, we get

(3x+2y)^2   =144

⇒9x^2  +4y^2  +2×3x×2y =144

⇒9x^2  +4y^2  =144−12xy

⇒9x^2  +4y^2  = 144−12×6 since xy=6

⇒9x^2  +4y^2  =144−72=72

∴9x^2  +4y^ 2 =72

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