If 3x+2y = 12and xy= 6,find the value 9x2+4y2
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Answer:
9x^2 +4y^ 2 =72
Step-by-step explanation:
3x+2y=12
Squaring both sides, we get
(3x+2y)^2 =144
⇒9x^2 +4y^2 +2×3x×2y =144
⇒9x^2 +4y^2 =144−12xy
⇒9x^2 +4y^2 = 144−12×6 since xy=6
⇒9x^2 +4y^2 =144−72=72
∴9x^2 +4y^ 2 =72
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