Question

If (3x + 2y) = 17 and xy = 5, then find the value of 9x²+4y²​

Answer 1

Answer:

229

Step-by-step explanation:

A/S -> (3x+2y) = 17

xy = 5

9x²+4y²

= (3x)²+(2y)²

= (3x+2y)²-(2*3x*2y)

= 17²-12xy

= 289-(12*5)

= 289-60

= 229

Answer 2

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Given:

• 3x + 2y = 17
• xy = 5

To find:

• Value of 9x² + 4y²

Solution:

We know that,

3x + 2y = 17

Squaring both sides,

(3x + 2y)² = 17²

As, (a+b)² = a² + b² + 2ab,

(3x + 2y)² = 9x² + 4y² + 12xy

=> 9x² + 4y² + 12xy = 289

=> 9x² + 4y² + 12*5 = 289

=> 9x² + 4y² + 60 = 289

=> 9x² + 4y² = 229.

Formula used:

• (a+b)² = a² + b² + 2ab

Hope it helps!!!!!!