Math, asked by singhanimeshkumar1, 1 month ago

if (3x - 2y) = 5 and xy = 6 , find the value of ( 27x³-8y³)

Answers

Answered by Sneha1825
2

above might be the answer

Attachments:
Answered by m74326827
1

Answer:

(3x - 2y) = 5

xy =6

( 27x³-8y³)

(3x)³-(2x)³

x³-y³=(x-y)(x²-xy-y²)

(3x-2y)(3x)²-(2y)²-2×3x×2y)

(3x-2y)((3x)-(2y))²-2×3x×2y)

(5)((5)²-12xy)

5(25-12×6)

5(47)

235

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