if (3x - 2y) = 5 and xy = 6 , find the value of ( 27x³-8y³)
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(3x - 2y) = 5
xy =6
( 27x³-8y³)
(3x)³-(2x)³
x³-y³=(x-y)(x²-xy-y²)
(3x-2y)(3x)²-(2y)²-2×3x×2y)
(3x-2y)((3x)-(2y))²-2×3x×2y)
(5)((5)²-12xy)
5(25-12×6)
5(47)
235
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