If 3x+2y=8 and the first quartile of x is 2 find the other quartiles
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x = 2
3×2+2y=8
6+2y=8
2y=8-6
2y=2
y=2/2
y=1
3×2+2y=8
6+2y=8
2y=8-6
2y=2
y=2/2
y=1
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