Math, asked by sajanasubba41, 10 months ago

if (3x-2y) :(x+3y)=5:6, find the value of x:y​

Answers

Answered by shilpanagpal2
0

Step-by-step explanation:

3x - 2y = 5

x + 3y = 6

multiply second eqn by 3

3x + 9y = 18

and subtract from 1 eqn

3x + 9y - 3x + 2y = 18 - 5

11y = 13

y = 13 / 11

put in first eqn

3x - 2y = 5

3x - 2 × 13/11 = 5

3x = 5+ 26 / 11

3x = 55+ 26 / 11

3x = 81 / 11

x = 81 / 11 × 3

x = 27 / 11

Answered by banani2112p8zd4n
1

Answer:

3x-2y = 5

x+3y 6

6(3x-2y) = 5(x+3y)

18x - 12y = 5x + 15y

18x - 5x = 15y - (-12y)

13x = 15y + 12y

13x = 27y

x = 13

y 27

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