if (3x-2y) :(x+3y)=5:6, find the value of x:y
Answers
Answered by
0
Step-by-step explanation:
3x - 2y = 5
x + 3y = 6
multiply second eqn by 3
3x + 9y = 18
and subtract from 1 eqn
3x + 9y - 3x + 2y = 18 - 5
11y = 13
y = 13 / 11
put in first eqn
3x - 2y = 5
3x - 2 × 13/11 = 5
3x = 5+ 26 / 11
3x = 55+ 26 / 11
3x = 81 / 11
x = 81 / 11 × 3
x = 27 / 11
Answered by
1
Answer:
3x-2y = 5
x+3y 6
6(3x-2y) = 5(x+3y)
18x - 12y = 5x + 15y
18x - 5x = 15y - (-12y)
13x = 15y + 12y
13x = 27y
x = 13
y 27
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