Question

If 3x^3-9x^2+kx+12 is divisible by it is also divisible by (x-3)​

Answer 1

Answer:

k =-4

Step-by-step explanation:

f(x-3) =0

x = 3

$g(x) = 3 {x}^{3}-9 {x}^{2 } + kx + 12$

g(3)=0

k = -4