Question

If 3x – 4 (64 – x) = 10, then the value of x is

Answer 1

Step-by-step explanation:

$\sf 3x - 4(64 - x) = 10$

$\sf 3x - 256 +4x = 10$

$\sf \implies 3x+4x-256 = 10$

$\sf \implies 7x-256 = 10$

$\sf \implies 7x = 256 +10$

$\sf \implies 7x = 266$

$\sf \implies x = \dfrac{266}{7}$

$\sf \implies x = 38$

So, the value of x is 38.

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Answer 2

Question:

If 3x – 4 (64 – x) = 10, then the value of x is ?

To find:

To find the value of x .

Answer:

$The \: value \: of \: x \: is \: \underline{ \: \sf \red{\frac{266}{193}} \: }$

Step-by-step explanation:

$\implies 3x - 4(64 - x) = 10$

$\implies 192x -3x-256+4x=10$

$\implies 193x - 256= 10------>1$

$\implies 193x =266$

$\implies \boxed{ \sf\pink{x = \frac{266}{193}}}$

$\therefore the \: value \: of \: x \: is \: \underline{ \: \sf \red{\frac{266}{193}} \: }$

Verification:

Substitute the value of x in eq( 1 )

$\implies 193(\frac{266}{193})-256 = 10$

$\implies 266-256=10$

$\implies \boxed{10 = 10}$

$\implies \boxed{L.H.S.=R.H.S.}$

Hence verified.

$\star\bold{ Note}$

An exchange of two elements of an ordered list with all others staying the same is known as transposition method .