If 3x + 4y = 12 and xy = 4. Find the value of 9x^2 + 16y^2
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3x + 4 y = 12
xy = 4
=>9x² + 16 y² = (3x)² + (4y)² .........(1)
=> As a²+ b² = (a + b) ² -2ab
So, (1) becomes
=>(3x) ² + (4y)² => (3x +4y )² - 2*3x*4y
=> 12² ⁻24*4
=> 144 - 86
=>58
xy = 4
=>9x² + 16 y² = (3x)² + (4y)² .........(1)
=> As a²+ b² = (a + b) ² -2ab
So, (1) becomes
=>(3x) ² + (4y)² => (3x +4y )² - 2*3x*4y
=> 12² ⁻24*4
=> 144 - 86
=>58
SIRGERARD10:
Ye (3x + 4y)^2 = 12^2 kaise aaya
batao na
as 3x + 4y is 12
put it equals 12 and xy =4
galat hai tera answer 48 hai answer
haa second last step m 24 * 4 = 96 tha ,
aur 144 - 96 = 48 which is right answer
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