if (3x-4y)³=27x³-64y³+ax²y+bxy² then find the value if a+b
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we know that
(a-b)^3=a^3-b^3-3a^2b+3ab^2
so here a=3x&b=-4y
(3x-4y )=27x^3-64y^3-108x^2y+144xy^2
so a= -108 and b=144
(a-b)^3=a^3-b^3-3a^2b+3ab^2
so here a=3x&b=-4y
(3x-4y )=27x^3-64y^3-108x^2y+144xy^2
so a= -108 and b=144
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