if 3x + 4y=8 and my= -32
find 9x^2+ 16y^2
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HEY MATE,LET ME HELP TO YOU WITH YOUR QUERY....
ACTUALLY,THERE'S AN ERROR IN YOUR QUERY,THAT IS,YOU WROTE "MY" INSTEAD OF "Y",BUT NO WORRIES,I WILL STILL CONSIDER IT "Y" AND HELP YOU....
GIVEN: 3x+4y=8,y=-32
TO FIND:9x^2+16y^2
SOLUTION: Substituing the value of y in the given equation,we get,
3x+4(-32)=8
3x-128=8
3x=136
x=136/3
Now,substituting the value of x and y in 9x^2+16y^2
=> 9[(136/3)^2]+16[(-32)^2]
=>18496+16384
=>34880
SO MATE,I HOPE,YOU GOT IT.....PLEASE CONSIDER MARKING MY ANSWER AS BRAINLIEST....:D
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