Question

if 3x + 4y is equals to 16 and x y is equals to 4 then find the value of 9x2 + 16y2.

Answer 1

Given 3x + 4y = 16 and xy = 4.

On squaring both sides, we get

(3x + 4y)^2 = (16)^2

9x^2 + 16y^2 + 24xy = 256

9x^2 + 16y^2 + 24(4) = 256

9x^2 + 16y^2 + 96 = 256

9x^2 + 16y^2 = 256 - 96

9x^2 + 16y^2 = 160.


Hope this helps!

Answer 2

Squaring both sides
(3x+4y)^2=(16)^2
9x2+16y2+24xy=256
9x2+16y2=256-24×4

9x2+16y2=160

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