Question

1/35 +12/35a +a^2 please factorise it

Answer 1

a² + 12/35 a + 1/35 = 0

a² + 1/7a + 1/5 a + 1/35 = 0

a ( a + 1/7 ) + 1/5 ( a + 1/7 ) = 0

( a + 1/7 ) ( a + 1/5 ) .....


Hope it will be helpful...

Answer 2

Answer:

- 1/7 and - 1/5

Step-by-step explanation:

We have the equation  

1/35 +12/35 a +a^2 to factorize. So we can write the equation in the form of ax^2 + bx + c = 0

So, a^2 + 12/35 a + 1/35 = 0

Now we can use the formula  

              X = - b ±√ b^2 – 4ac/ 2a   where a = 1 b = 12/35 and c = 1/35

              X = -12/35 ±  √(12/35)^2 – 4(1)(1/35) / 2(1)

               X = -12/35 ± √144/1225 – 4(1/35)(1) / 2

              X = - 12/35 ± 4 / 1225 / 2

               X = - 12 / 35 ± 2 / 35 / 2

              X = -12/35 + 2/35 = - 1/7 and -12/35 - 2/35 = - 1/5

              X = - 1/7 and X = - 1/5