Question

If (3x-4y) units, (7x+y) units,(x+12y) units and (3y- 4x) units are the lengths of the sides a quadrilateral, then find the perimeter of the quadrilateral

Answer 1

Answer:

Since it is an equilateral triangle, the

lengths of the sides are equal 1

So, x + 3y = 3x + 2y = 2 = 4x + 5y + 1

2

... x + 3y = 3x + 2y - 2

..y = 2x - 2 2x - y = 2...(1)

1 Also, 4x + y + 1 = x + 3y 2

.. 8x + y +2 = 2x + 6y

6x + 2 = 5y

6x - 5y = = -2 ...(2)

Multiplying eq(1) by 5 we get, 10x - 5y 10 ...(3) Subtracting eq(2) from eq(3) we get, 4x = 12 ⇒ x = 3

..y = 2x - 2 = 4

The length of one side of equilateral triangle = x + 3y =3+3(4) = 15units