Math, asked by sandeepmolamma, 11 months ago

If 3x + 5y + 7z = 49 and 9x + 8y + 21z = 126, then what is the value of y?

Answers

Answered by omkar20601
3

Answer:

here you go answer for this question is y=3

Attachments:
Answered by ansarikhatoon96
2

Answer:

Step-by-step explanation:

3x+5y+7z=49---1 summikaran

9x+8y+21z=126--2 summikaran

Now multiplied by 3 to 1

Example

3x*3=9x

5y*3=15y

7z*3=21z

49*3=147

Now put

9x+15y+21z=147

- 9x+8y+21z=126

=0+7y+0=21

Y=21/7

Y=3

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