If 3x = cosec θ and 3/x = cot θ, find the value of 3 (x^2 + 1/x^2).
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Since it is given that 3x=cosec theta and 3/x=cot theta
so,x=cosec theta/3 & 1/x=cot theta/3
so,3(cosec theta^2/9 - cot^2/9)
3[1/9(cosec theta^2 - cot theta^2). -(1)
as we know that 1 + cot theta^2=cosec theta^2
1=cosec theta^2 - cot theta ^2. -(2)
putting value of (2) in (1)
1/3(1)
1/3
I would suggest u to first write the given solution in copy as given for better clearance of your doubts and if not understood then type it.
so,x=cosec theta/3 & 1/x=cot theta/3
so,3(cosec theta^2/9 - cot^2/9)
3[1/9(cosec theta^2 - cot theta^2). -(1)
as we know that 1 + cot theta^2=cosec theta^2
1=cosec theta^2 - cot theta ^2. -(2)
putting value of (2) in (1)
1/3(1)
1/3
I would suggest u to first write the given solution in copy as given for better clearance of your doubts and if not understood then type it.
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