if 3x log5base 2+2log5 base x =128
then find the value of x ?
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Answer:
x=5 please keep me in brain list
Step-by-step explanation:
Let us assume 2log25=x
Now taking logarithm with base 2 on both sides we get,
log22log25=log2x [Since logaax=x ]
or,log25=log2x
or,x=5
Actually you can this as a property in logarithm,
mlogmn=n
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