Question

if (3x-y)^7=a0x^7-a1x^6y+a2x^5y^2-a3x^4y^3+a4x^3y^4-a5x^2y^5+a6xy^6-a7y^7, then find the value of a0-a1+a2-a3+a4-a5+a6-a7

Answer 1

Sorry I have no answer but this question MAY BE wrong !⚠

Answer 2

Answer:

128

Step-by-step explanation:

let x=y=1

hence eq will become a0-a1...-a7

(multiplied by powers of 1)

hence

(3x-y)^7=a0-a1...-a7

hence 2^7=128