If 3x2 – 2kx + m = 0, find k when x = 2 and m = 3.
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Answered by
24
Hi mate
Here is ur answer⬇️⬇️
3x^2 - 2kx + m = 0
3(2)^2 - 2(2)k + 3 = 0
3(4) - 4k + 3 =0
12 + 3 -4k = 0
-4k=-15
➡️k=15/4
I hope this will help you
⚛️mark as brainliest ⚛️
Here is ur answer⬇️⬇️
3x^2 - 2kx + m = 0
3(2)^2 - 2(2)k + 3 = 0
3(4) - 4k + 3 =0
12 + 3 -4k = 0
-4k=-15
➡️k=15/4
I hope this will help you
⚛️mark as brainliest ⚛️
Answered by
9
Please Mark As Brainliest
Here is the full solution....
3x^2-2kx+m = 0
x = 2 and m = 3
now putting the value of "x" and "m" ――――
3(2)^2 - 2k(2) + 3 = 0
3×4 - 4k + 3 = 0
12 + 4k + 3 = 0
4k = -12 - 3
4k = - 15
k = -15/4 answer...
Hope this'll will help you buddy
Here is the full solution....
3x^2-2kx+m = 0
x = 2 and m = 3
now putting the value of "x" and "m" ――――
3(2)^2 - 2k(2) + 3 = 0
3×4 - 4k + 3 = 0
12 + 4k + 3 = 0
4k = -12 - 3
4k = - 15
k = -15/4 answer...
Hope this'll will help you buddy
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