If 3x² + xy – 2y' = 0 and 2x² – 3xy + y² =-1 then (x,y) II
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Answer:
3x+2y-1
=(3) 2+(2)-2-1
=6 - 4 - 1
=2 - 1
= 1
Step-by-step explanation:
#hope it helps you
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