if 4, 12, 20, and so on are in AP then the sum of the first 20 terms is
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Hiii
Good morning
4,12,20,.......,20terms
a = 4
d= 12 - 4
d= 8
n = 20
S(n) = n/2 [ 2a+ (n - 1) d]
S(20) = 20/ 2 [ 2(4) + (20 - 1) 8]
S(20)= 10[ 8 + (19)8]
S(20) = 10 [ 8 + 152]
S(20)= 10[160]
S(20) = 1600
May it is helpful for you.
✌✌✌Have a great day ✌✌✌
Good morning
4,12,20,.......,20terms
a = 4
d= 12 - 4
d= 8
n = 20
S(n) = n/2 [ 2a+ (n - 1) d]
S(20) = 20/ 2 [ 2(4) + (20 - 1) 8]
S(20)= 10[ 8 + (19)8]
S(20) = 10 [ 8 + 152]
S(20)= 10[160]
S(20) = 1600
May it is helpful for you.
✌✌✌Have a great day ✌✌✌
harsimransingh4548:
hello ji
hello ji
good morning
Answered by
0
Answer:
Step-by-step explanation:
4+12+20+28........20th terms
S=n/2[2a+(n-1)d] put the value in this
Where
D diff between digits 8
A first digit 4
N no of digits 20
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