Question

If 4^2x-1 - 16^x-1 = 384, find the value of x. {Class 9}

Answer 1

$\huge{\underline{\underline{\bf{SOLUTION-}}}}$

42x−1−16x−1=348

⇒42x−1−42(x−1)=384

⇒42x−1−42x−2=384

⇒42x−1[1−1/4]=384

⇒42x−1(43)=384

⇒42x−1=3384×4

⇒42x−1=128×4

⇒42x−1=512

⇒42x−1=29

⇒22(2x−1)=29

⇒4x−2=9         [Comparing exponents]

⇒4x=11

⇒x=411

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Answer 2

$\huge{\underline{\underline{\bf{SOLUTION-}}}}$

42x−1−16x−1=348

⇒42x−1−42(x−1)=384

⇒42x−1−42x−2=384

⇒42x−1[1−1/4]=384

⇒42x−1(43)=384

⇒42x−1=3384×4

⇒42x−1=128×4

⇒42x−1=512

⇒42x−1=29

⇒22(2x−1)=29

⇒4x−2=9         [Comparing exponents]

⇒4x=11

⇒x=411

I Hope Help You !!!

it's master335