Question

if 4^44+4^44+4^44+4^44=4^x.Find x

Answer 1

Here the answer of your question

Answer 2

Answer:

Required value of x is 45.

Step-by-step explanation:

Given,

${4}^{44} + {4}^{44} + {4}^{44} + {4}^{44} = {4}^{x}$

Here we want to find value of the x.

${4}^{44} + {4}^{44} + {4}^{44} + {4}^{44} = {4}^{x} \\ 4 \times {4}^{44} = {4}^{x} \\ {4}^{1 + 44} = {4}^{x} \\ {4}^{45} = {4}^{x} \\ x = 45$

Here applied formula,

${x}^{a} \times {x}^{b} = {x}^{a + b}$

${x}^{a} = {x}^{b} \\ a = b$

This is a problem of Power of indices

Some formulas of Power of indices,

${x}^{0} = 1 \\ {x}^{1} = x \\ {x}^{a} \times {x}^{b} = {x}^{a + b} \\ \frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b} \\ {x}^{ {y}^{a} } = {x}^{ya} \\ {x}^{ - 1} = \frac{1}{x} \\ {x}^{a} \times {y}^{a} = {(xy)}^{a}$