which term of the sequence 5, 14, 23 ....... is 239?
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Answered by
3
Hlo
Here ia your answer
a=5 , d=9 , l=239
l=a+(n-1)d
239=5+(n-1)9
234=(n-1)9
(n-1)=26
n=27
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Answered by
6
by using
... tn= a+(n-1) d
239=5+ n-1 ×9
239-5
234/9 ={n-1}
26 = n-1
n= 26+1
n=27
term is 27th
... tn= a+(n-1) d
239=5+ n-1 ×9
239-5
234/9 ={n-1}
26 = n-1
n= 26+1
n=27
term is 27th
wow ! thank u so much
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