If 4/5 ,a,12/5 are three consecutive terms of an ap ,find a
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3
4/5 a,12/5,.......
a=4/5
d=a2-a1
=5a-4/5
Answered by
40
Answer:
a=4/5
a2=a
a3=12/5
d=a2-a
=a3-a
a2-a=a3-a2
a-4/5=12/5-a
5a/5-4/5=12/5-5a/5 (Taking LCM)
5a-4=12-5a (Dividing throughout by 5)
5a+5a=12+4
10a=16
a=16/10
a=8/5
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