Question

if 4/5,a,2 are three consecutive terms of an AP,then find value of a

Answer 1

here's your answer.......

Answer 2

Answer:

$Value \: of \: a = \frac{7}{5}=1.4$

Step-by-step explanation:

$Given \: \frac{4}{5} , a , 2\: are\\ \:three \:consecutive\: terms\: of \:an\: A.P$

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Difference of any two consecutive terms in A.P is equal

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$a-\frac{4}{5}=2-a$

$\implies 2a = 2+\frac{4}{5}$

$\implies 2a = \frac{10+4}{5}$

$\implies 2a = \frac{14}{5}$

$\implies a = \frac{14}{2\times 5}$

$\implies a = \frac{7}{5}=1.4$

Therefore,

$Value \: of \: a = \frac{7}{5}=1.4$

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