if 4÷5 , a, 2 three consecutive term of an A.P. then find a.
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they are in AP so
a2-a1=a3-a2
a-4/5=2-a
5a-4/5=2-a
5a-4=10-5a
5a+5a=10+4
10a=14
a=14/10
a=7/5
a2-a1=a3-a2
a-4/5=2-a
5a-4/5=2-a
5a-4=10-5a
5a+5a=10+4
10a=14
a=14/10
a=7/5
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