Question

If 4.80 mol of Nitrogen gas occupies a volume of 118.0 L, what volume will
4.40 mol of nitrogen occupy under the same conditions of temperature and
pressure??

Answer 1

Answer:

108.17 L

Explanation:

4.80 mol - 118 L

1 mol - 118/4.80 L

4.40 mol = 118/4.80 × 4.40 = 108.17 L