If 4 biscuits are distributed among 3 children then the probability of receiving at least one biscuit by the 1st child is
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If 4 biscuits are distributed among 3 children, then the probability of receiving at least one biscuit by the 1st child is 2/3.
1) In the question, the probability of the first child getting atleast one biscuit has been asked. This means the child may get either 0, 1 or more biscuits.
2) Probability of the first child getting no biscuit at all = 1/3 (since there are three children in total).
3) Therefore, probability of the first child getting atleast one biscuit = 1 - Probability of getting no biscuits at all = 1 - 1/3 = 2/3.
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Answer:
1-(2/3)^4
Step-by-step explanation:
probability of not getting a biscuit is 2/3
as there are 4 biscuits it is (2/3)^4
probability of getting a biscuit is 1-(2/3)^2
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