Question

If 4 cos sq A -3 =0 find tan sq A +COS SQ A

Answer 1

Answer:

LHS = sin(90 - A ) * cos ( 90 - A )

= CosA sinA ----( 1 )

RHS = tanA / ( 1 + tan² A )

= tan A / sec² A

= ( SinA/cosA ) / ( 1/ cos² A )

= ( SinA cos² A ) / cosA

= SinAcosA ----( 2 )

From ( 1 ) and ( 2 ) ,

LHS = RHS