If 4 cos~theta- 3=0 then sin theta=?
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Answer:
Step-by-step explanation:
4 cos Ф-3=0
4 cosФ=3
cosФ=3÷4
Now
as we know that cos Ф=b÷h
b÷h=3÷4
So
base=3 and hypotenus=4
Now we have to calculate the perpendicular as the formula of sinФis p÷h
So
p²=h²-b²
p²=4²-3²
p²=16-9
p²=7
p=√7
we have perpendicular(p)=√7
Again
sinФ=perpendicular/hypotenus
sinФ=√7/4
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