If 4 cosA +4sinA-5 = O. find the value of sinA
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Answer:
4 cos A+4 SinA=5
4cos A=5-4SinA
Squaring both sides; we get
16 cos^2A =25-40 SinA+16 sin^2 A
16-16 sin^2A=25-40SinA+ 16 Sin^2 A
32sin^2 A+40 sinA+9=0 Now
using quadratic formula;
a=32,b=40,c=9,x=SinA
such that SinA=x. Simplify and complete your self.
Step-by-step explanation:
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