Question

If 4 cot 0 = 3, show that [sin 0 - cos 0/sin 0+cos 0]=1/7
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Answer 1

Answer:

Answer:

1/7

Step-by-step explanation:

4 cotA = 3 → cotA = 3/4

\begin{gathered} \small{ \implies \frac{sin \theta - cos\theta}{ sin \theta + cos\theta} } \\ \\ \implies \frac{ \frac{sin \theta - cos\theta}{sin \theta} }{ \frac{sin \theta + cos\theta}{sin \theta}} \\ \\ \implies \frac{ \frac{sin \theta}{sin \theta} - \frac{cos\theta}{sin \theta} }{ \frac{sin \theta}{sin\theta} + \frac{cos\theta}{sin \theta} } \\ \\ \implies \small{ \frac{1 - cot\theta}{1 + cot \theta}} \end{gathered}

⟹

sinθ+cosθ

sinθ−cosθ

⟹

sinθ

sinθ+cosθ

sinθ

sinθ−cosθ

⟹

sinθ

sinθ

+

sinθ

cosθ

sinθ

sinθ

−

sinθ

cosθ

⟹

1+cotθ

1−cotθ

\begin{gathered}\implies \frac{1-\frac{3}{4}}{1+\frac{3}{4}} \\\\\implies \frac{\frac{4-3}{4}}{\frac{1+3}{4}} \\\\\implies \frac{1}{7}\end{gathered}

⟹

1+

4

3

1−

4

3

⟹

4

1+3

4

4−3

⟹

7

1

Proved.

Step-by-step explanation:

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Answer 2

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