if 4 cot theta is equals to 3 show that sin theta minus cos theta upon sin theta + cos theta is equals to one upon 7
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Given
- 4 cot Ф = 3
To prove
- (sin Ф - cos Ф) / (sin Ф + cos Ф) = 7
Explanation
- given that
⇨ 4 cot Ф = 3
⇨ cot Ф = 3 / 4
⇨ tan Ф = 4 / 3
- we need to prove
(sin Ф + cos Ф) / (sin Ф - cos Ф) = 7
⇨ LHS = (sin Ф + cos Ф) / (sin Ф - cos Ф)
dividing both numerator and denominator by cos Ф
⇨ LHS = [(sin Ф + cos Ф)/cos Ф] / [(sin Ф - cos Ф)/cos Ф]
⇨ LHS = ( tan Ф + 1 ) / ( tan Ф - 1 )
substituting value of tan Ф
⇨ LHS = ( (4/3) + 1 ) / ( (4/3) - 1 )
⇨ LHS = ( (4+3)/3 ) / ( (4-3)/3 )
⇨ LHS = ( 7/3 ) / ( 1/3 )
⇨ LHS = ( 7/3 ) × ( 3 ) = 7 = RHS
Proved .
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