Question

solve above question?​

Answer 1

Explanation:

this is the answer for the question

Answer 2

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A loop ABCDEFA of straight edges has six corner points A(0,0,0), B(5,0,0), C(5,5,0), D(0, 5, 0), E(0, 5, 5) and F(0, 0, 5). The magnetic field in this region is vector B = (3i + 4k)T. The quantity of flux through the loop ABCDEFA (in Wb) is ______ .

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Quantity of flux through the loop ABCDEFA

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• Area of ABCD =25 $\sf{\hat k}$
• Area of ADEF=25 î

• Magnitude of magnetic field = $\sf{(3 \hat i+4\hat j )T}$

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$\bf{\phi = B.A}$

where,

• Φ= Magnetic flux,
• B =magnitude of the magnetic field,
• A =area of the surface

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firstly we find the net Area,so

Total area=  area of ABCD+ area of ADEF

A= 25î + 25 $\hat k$

Put the value of area and magnitude of magnetic field in the given formula,

Φ=B.A

ϕ = 25 x 3 + 25 x 4

$\boxed{\sf{\pink{\phi = 175wb \bigstar }}}$

hence,The quantity of flux through the loop ABCDEFA 175Wb

(For Figure refer the attachment)

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More info-

• Magnetic flux is total no. of magnetic field lines which passes through a given area.

• Magnetic flux is the product of the magnetic field and  perpendicular area that it crosses.

• Magnetic flux = Magnetic field × Area × (angle between the planar area and the magnetic flux)

The equation is:

Φ = B A cos(θ)

Where:

Φ: Magnetic Flux

A: Area

B: Magnetic field

θ: angle between a perpendicular vector to the area and the magnetic field

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