Question

if 4 different biscuits are distributed among three children then the probability of receiving at least one biscuit by the first child is​

Answer 1

Answer:

1/3

Step-by-step explanation:

the probablity is 1/3

Answer 2

The probability of receiving at least one biscuit by the first child is​  $\frac{2}{3}$

Step-by-step explanation:

4 different biscuits are distributed among three children

each child has the same probability of not getting any in particular with first child

probability of not getting any biscuit = $\frac{1}{3}$

then

the probability that first child receive atleast one biscuit

= total probability - probability of not getting any biscuit

∵ p(E) + p( not E) = 1

= $1-\frac{1}{3}$

= $\frac{3-1}{3}$

= $\frac{2}{3}$

hence ,

The probability of receiving at least one biscuit by the first child is​  $\frac{2}{3}$

#Learn more:

8 biscuits are distributed among 11 children, find the probability that a particular child receives 5 biscuits

https://brainly.in/question/6156687