If 4 g of NaOH is dissolved in 36 g of H2O ,determine the molarity of the solution. (specific gravity of the solution is 1 g/ml)
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Mass of NaOH=4 g
Number of moles of NaOH=40 g4 g=0.1 mol
Mass of H2O=36 g
Number of moles of H2O=18 g36 g=2 mol
Mole fraction of water =No. of moles of water+No. of moles of NaOHNumber of moles of H2O
=2+0.12=2.12=0.95
Mole fraction of NaOH =No. of moles of NaOH+No. of moles of waterNumber of moles of NaOH
=2+0.10.1=2.10.1=0.047
Mass of solution = mass of water + mass of NaOH=36g+4 g=40 g
Volume of solution =40×1=40 mL.
( Since specific gravity of solution is =1 g mL−1)
Molarity of solution =
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