Question

If 4 gm naoh is present in 500 ml solution then determine the normality of the solution

Answer 1

wt. NaOH= 4 g

V = 500 ml

Molar mass = 23 + 16 + 1 = 40 g/ mol

Moles of NaOH (n) = wt./ Mol. wt.

= 4/ 40

n = 0.1 moles

Molarity = no. of moles of solute/Vol. of solution(in Litres)

= 0.1×1000/500

M= 0.2 Molar

Normality= Molarity/Acidity of base(NaOH)

= 0.2/1

N = 0.2 Normal