if -4 is a root of quadratic equation X square + bx - 4 and the quadratic equations X square + 3 X + K is equal to zero has equal roots find the value of k
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hey mate
given here
first given equation
x^2+bx+4=0. ......(1)
and -4 zeros of equation of (1).
secondary given equation
x^2+3x+k=0. ....(2)
a/c ...
-4 equation of (1) and (2)
are zeros .
so, x=-4 satisfy equation (2).
so,
put x=-4 ,in (2).
we get ,
=>(-4)^2 +3 × (-4)+k=0
=>16 - 12 + k=0
=>4+k=0
=> k= -4.
thus:
the value of k will be
= -4.
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