if -4 is a root of the quadratic equation X square + kx - 4 is equal to zero and the quadratic equation X square + PX + K is equal to zero has equal roots then find the value of P and K
Answers
Answered by
3
Answer:
Step-by-step explanation:
-4 is the root of equation x²+kx-4
Put value of x that is -4
(-4)²+k(-4)-4=0
16-4k-4=0
12-4k=0
12=4k
k=12/4
k=3
Put value of k in second equation
x+px+3
This equation has equal roots
So,
Discriminant (b²-4ac)=0
a=1 , b=p ,c=3
p²-4×3×1=0
p²-12=0
p²=12
p=√12
p=2√3,-2√3
Hence k=3
p=2√3,-2√3
Similar questions