If -4 is a root of the quadratic equation xsquare+px-4=0and quadratic equation xsquare+px+k=0 has equal roots find the value of k
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Answer: p(x)=x^2+px-4=0 -4 is a root of p(x) p(-4)= (-4)^2-4p-4=0 16-4p-4=0 p=3 x^2+px+k=0 has equal roots Since p=3 x^2+3x+k=0 has equal roots Therefore, a=1, b=3, c=k b^2-4ac=0 3^2-4*1*k=0 9-4k=0 k=9/4
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