If 4 is a zero of p(x) = x² – kx + 12 find another zero ?
(A) 7
(B) -7
(C) 3
(D) -4
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Answer:
the another zero is 7
Step-by-step explanation:
in putting 4 in the place of x
(4)^2-k(4)+12=0
16-4k+12=0
4k=28
k=7
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