Question

If -4 is a zero of the polynomial p(x)=x^2+11x+k, then calculate the value of k.

Answer 1

[Sujeet ]

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ACCORDING TO THE QUESTION:

Putting the value of Zero in Polynomial:-

x²+11x+k

p(-4)=x²+11x+k

=) {-4)²+11(-4)+k=0

=} 16+(-44)+k=0

=) 16-44+k=0

-28+k=0

k=28

Thanks!!!

Answer 2

Putting the value of zero in polynomial

P(-4) = x^2+11x+k

P(-4) = x^2+11x+k= (-4) ^2+11(-4)+k=0

P(-4) = x^2+11x+k= (-4) ^2+11(-4)+k=0= 16+(-44) +k=0

P(-4) = x^2+11x+k= (-4) ^2+11(-4)+k=0= 16+(-44) +k=0= -28 + k = 0

P(-4) = x^2+11x+k= (-4) ^2+11(-4)+k=0= 16+(-44) +k=0= -28 + k = 0K = 28 + 0

P(-4) = x^2+11x+k= (-4) ^2+11(-4)+k=0= 16+(-44) +k=0= -28 + k = 0K = 28 + 0K = 28

Thanks!!