if -4 is zeroes of polynomial x2-x-{2+2k}
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Hey friend!!
Good evening..
Here is ur answer..
Hope it may help you..
Thank you :) :)
Good evening..
Here is ur answer..
Hope it may help you..
Thank you :) :)
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4
Hey there!
Given f(x) = x² - x - (2+2k)
Also, -4 is a zero of polynomial.
So f(-4) = 0
=> f(-4) = (-4)²- (-4) - (2+2k) = 0
=> 16 + 4 - 2 - 2k = 0
=> 18 -2k = 0
=> 18 = 2k
=> k = 18/2
=> k = 9
Therefore , Value of k is 9 .
Given f(x) = x² - x - (2+2k)
Also, -4 is a zero of polynomial.
So f(-4) = 0
=> f(-4) = (-4)²- (-4) - (2+2k) = 0
=> 16 + 4 - 2 - 2k = 0
=> 18 -2k = 0
=> 18 = 2k
=> k = 18/2
=> k = 9
Therefore , Value of k is 9 .
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