if 4 m + 8,2 m^2 + 3m + 6, 3m^2 + 4 + 4 are three consecutive term of an ap find m
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Heya!!
______________________________
2m² + 3m + 6 - { 4m + 8 } = 3m² + 8 - {
2m² + 3m + 6 }
Becoz these terms are in A.P so, the common Difference must be same
=>
2m² - m - 2 = m² - 3m + 2
=>
m² + 2m -4 = 0
=>
m² + 2 ( m ) ( 1 ) + 1 - 1 - 4 = 0
=>
( m + 1 )² = 5
=>
( m + 1 ) = √5 OR ( m + 1 ) = -√5
=>
m = √5 - 1 OR m = -√5 -1
______________________________
2m² + 3m + 6 - { 4m + 8 } = 3m² + 8 - {
2m² + 3m + 6 }
Becoz these terms are in A.P so, the common Difference must be same
=>
2m² - m - 2 = m² - 3m + 2
=>
m² + 2m -4 = 0
=>
m² + 2 ( m ) ( 1 ) + 1 - 1 - 4 = 0
=>
( m + 1 )² = 5
=>
( m + 1 ) = √5 OR ( m + 1 ) = -√5
=>
m = √5 - 1 OR m = -√5 -1
palaktyagi3:
thanku very much bro
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