Math, asked by Relango, 1 year ago

if 4( np3)=(n+1)p3 find the value of n

Answers

Answered by rajamrit98
1

4np3=p3n+p3

4p3n-p3n=p3

3p3n=p3

n=p3/3p3

n=1/3

Answered by ihrishi
0

Answer:

\huge{4(np^{3} ) = (n + 1) {p}^{3}  \\ 4n {p}^{3}  = n {p}^{3}  +  {p}^{3}  \\ 4n {p}^{3} - n {p}^{3} =  {p}^{3} \\ 3n {p}^{3} =   {p}^{3}  \\ n =  \frac{ {p}^{3} }{3{p}^{3} }  \\  \implies \: n =  \frac{1}{3}} \\

Similar questions