Question

If 4 ohm and 2 ohm resistors are connected in series and 6V potential difference is applied
* What is the current in the circuit
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Answer 1

4 ohm and 2 ohm resistors are connected in series.

In series circuit, the current flows the same in all resistors but the potential difference is different so that is why we are taking the total resistance to total potential difference.

Rseries = R1 + R2 = 2 + 4 = 6 ohm

Potential difference = 6 Volts

V = IR

6 = I × 6

I (current) = 1 Ampere

Hope it helps you ❤

Answer 2

The current in the circuit is 0.5 A.

Here, first we have to find the combined resistance to find the current flowing.

i.e,  The combines resistance can be calculated by = $R_1 + R_2$

                                                                                     = 6 + 2

                                                                                     = 8 ohms.

Thus, the current flowing can be calculated using the formula, V = iR

p.d applied to two resistors of 6 ohms and 2 ohms (V) = 4V

Hence, I = $\frac{V}{R}$

               = $\frac{4}{8}$

              = 0.5 A

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