Question

Mounica took a loan of ₹ 1,00,000 at 12% per annum compounded half yearly. If she paid

₹1,12,360, find the time period for which she took the loan.
please answer...​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Time=1\:year}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Principal(p) = 100000 \: rupees \\ \\ \tt: \implies Amount(a) = 112360 \: rupees \\ \\ \tt: \implies Rate\%(r) = 12\% \\ \\ \red{\underline \bold{To \: find :}} \\ \tt: \implies Time(t) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A = p(1 + \frac{ \frac{r}{2} }{100} )^{2t} \\ \\ \tt: \implies 112360 = 100000 \times (1 + \frac{12}{2 \times 100} )^{2t} \\ \\ \tt: \implies \frac{112360}{100000} =( 1 + 0.06)^{2t} \\ \\ \tt: \implies 1.1236 =( 1.06)^{2t} \\ \\ \tt: \implies (1.06)^{2} = (1.06)^{2t} \\ \\ \tt: \implies 2= 2t \\ \\ \green{\tt: \implies t = 1 \: year} \\ \\ \green{\tt \therefore Time \:for \: taken \: loan \: is \: 1 \: year}$

Answer 2

Answer:

this is the answer pls check