if 4 sin theta=3 cos theta find the value of 12 sin theta-7cos theta/8sin theta + 3cos theta
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Answered by
71
Given 4 SinФ = 3 CosФ
=> Tan Ф = 3/4
LHS: [ 12 Sin Ф - 7 Cos Ф ] / [ 8 Sin Ф + 3 Cos Ф ]
Divide the numerator and denominator by cosФ, as CosФ ≠ 0.
= [ 12 TanФ - 7 ] / [ 8 TanФ + 3 ] , substitute the value of TanФ
= [ 12*3/4 - 7 ] / [ 8 * 3/4 + 3 ]
= 2/9
=> Tan Ф = 3/4
LHS: [ 12 Sin Ф - 7 Cos Ф ] / [ 8 Sin Ф + 3 Cos Ф ]
Divide the numerator and denominator by cosФ, as CosФ ≠ 0.
= [ 12 TanФ - 7 ] / [ 8 TanФ + 3 ] , substitute the value of TanФ
= [ 12*3/4 - 7 ] / [ 8 * 3/4 + 3 ]
= 2/9
kvnmurty:
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Answered by
46
Answer is in attachment.
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