Question

if 4 tan theta is equal to 3 evaluate 4 sin theta minus cos theta + 1 by 4 sin theta + cos theta minus one​

Answer 1

Answer:

LET THETA BE A

Step-by-step explanation:

4tanA=3

tanA=3/4

now by pythogaras theorem , hypotenuse= 5

sinA=3/5

COSA=4/5

now 4sinA + cosA-1=

4x3/5 +4/5 -1

=16/5 -1

=11/5

Answer 2

given : 4 tan @= 3 ( theta taken as @)

tan @ = 3/4

tan @ = p/b. ( p= perpendicular ; b= base)

p = 3

b= 4

by using Pythagoras theorem we get h = √ p²+b²

h = √9+16

h = 5

sin@ = p/h

= 3/5

cos@= b/h

= 4/5

to evaluate = (4sin@ - cos@ + 1)/ (4sin@+cos@-1)

=( 12/5 - 4/5 + 1)/(12/5+4/5-1)

= {(12-4+5)/5}/{(12+4-5)/5}

= (13/5)/(11/5)

= 13/11